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(1/25)^x-2=125^x/3
We move all terms to the left:
(1/25)^x-2-(125^x/3)=0
Domain of the equation: 25)^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/25)^x-(125^x/3)-2=0
We get rid of parentheses
(+1/25)^x-125^x/3-2=0
We calculate fractions
-3125x^2)/25^x*3)+()/25^x*3)+(-2=0
We can not solve this equation
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